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11222004121133 = 13863231086241
BaseRepresentation
bin1010001101001101001110…
…0100011011111000101101
31110201210221202120112102012
42203103103210123320231
52432330131023334013
635511152330211005
72235522503112101
oct243232344337055
943653852515365
1011222004121133
113637252850a93
121312a96583a65
136352cc3a8c40
142ab20db8b901
15146d9b7c31a8
hexa34d391be2d

11222004121133 has 4 divisors (see below), whose sum is σ = 12085235207388. Its totient is φ = 10358773034880.

The previous prime is 11222004121099. The next prime is 11222004121267. The reversal of 11222004121133 is 33112140022211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7577043485449 + 3644960635684 = 2752643^2 + 1909178^2 .

It is a cyclic number.

It is not a de Polignac number, because 11222004121133 - 240 = 10122492493357 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11222004121099 and 11222004121108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11222004126133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431615543108 + ... + 431615543133.

It is an arithmetic number, because the mean of its divisors is an integer number (3021308801847).

Almost surely, 211222004121133 is an apocalyptic number.

11222004121133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11222004121133 is a deficient number, since it is larger than the sum of its proper divisors (863231086255).

11222004121133 is an equidigital number, since it uses as much as digits as its factorization.

11222004121133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 863231086254.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11222004121133 its reverse (33112140022211), we get a palindrome (44334144143344).

The spelling of 11222004121133 in words is "eleven trillion, two hundred twenty-two billion, four million, one hundred twenty-one thousand, one hundred thirty-three".

Divisors: 1 13 863231086241 11222004121133