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112221101222120 = 2351117659109720753
BaseRepresentation
bin11001100001000010000010…
…110111111110100011101000
3112201100020021111100110120202
4121201002002313332203220
5104202112303403101440
61034401355011211332
732431464334431632
oct3141020267764350
9481306244313522
10112221101222120
113283677a050720
121070524b8a6b48
134a8053471a637
141d9d75d133a52
15ce91dd408615
hex661082dfe8e8

112221101222120 has 256 divisors, whose sum is σ = 292377769516800. Its totient is φ = 38312136540160.

The previous prime is 112221101222119. The next prime is 112221101222123. The reversal of 112221101222120 is 21222101122211.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 112221101222092 and 112221101222101.

It is not an unprimeable number, because it can be changed into a prime (112221101222123) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5407453664 + ... + 5407474416.

It is an arithmetic number, because the mean of its divisors is an integer number (1142100662175).

Almost surely, 2112221101222120 is an apocalyptic number.

112221101222120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112221101222120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (146188884758400).

112221101222120 is an abundant number, since it is smaller than the sum of its proper divisors (180156668294680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112221101222120 is a wasteful number, since it uses less digits than its factorization.

112221101222120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22548 (or 22544 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 112221101222120 its reverse (21222101122211), we get a palindrome (133443202344331).

Subtracting from 112221101222120 its reverse (21222101122211), we obtain a palindrome (90999000099909).

The spelling of 112221101222120 in words is "one hundred twelve trillion, two hundred twenty-one billion, one hundred one million, two hundred twenty-two thousand, one hundred twenty".