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11223212113 = 35323317731
BaseRepresentation
bin10100111001111010…
…01010000001010001
31001222011110020200201
422130331022001101
5140441120241423
65053400215201
7545056505011
oct123475120121
931864406621
1011223212113
11483a235413
12221276a501
13109b24b119
147867b5c41
1545a4812ad
hex29cf4a051

11223212113 has 4 divisors (see below), whose sum is σ = 11223565168. Its totient is φ = 11222859060.

The previous prime is 11223212083. The next prime is 11223212129. The reversal of 11223212113 is 31121232211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121232211 = 50361871237.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11223212113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11223212153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123543 + ... + 194188.

It is an arithmetic number, because the mean of its divisors is an integer number (2805891292).

Almost surely, 211223212113 is an apocalyptic number.

It is an amenable number.

11223212113 is a deficient number, since it is larger than the sum of its proper divisors (353055).

11223212113 is an equidigital number, since it uses as much as digits as its factorization.

11223212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 353054.

The product of its digits is 144, while the sum is 19.

Adding to 11223212113 its reverse (31121232211), we get a palindrome (42344444324).

The spelling of 11223212113 in words is "eleven billion, two hundred twenty-three million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 35323 317731 11223212113