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140441120241423 = 346813706747141
BaseRepresentation
bin11111111011101011111111…
…000101010111011100001111
3200102021001002010210121102120
4133323223333011113130033
5121401441403240211143
61214405432052424023
741403351611336631
oct3773537705273417
9612231063717376
10140441120241423
11408268210a1641
121390251b018013
13604970521b231
14269755a748a51
1511382e0e00383
hex7fbaff15770f

140441120241423 has 4 divisors (see below), whose sum is σ = 187254826988568. Its totient is φ = 93627413494280.

The previous prime is 140441120241421. The next prime is 140441120241559. The reversal of 140441120241423 is 324142021144041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140441120241423 - 21 = 140441120241421 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140441120241421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23406853373568 + ... + 23406853373573.

It is an arithmetic number, because the mean of its divisors is an integer number (46813706747142).

Almost surely, 2140441120241423 is an apocalyptic number.

140441120241423 is a deficient number, since it is larger than the sum of its proper divisors (46813706747145).

140441120241423 is an equidigital number, since it uses as much as digits as its factorization.

140441120241423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46813706747144.

The product of its (nonzero) digits is 24576, while the sum is 33.

Adding to 140441120241423 its reverse (324142021144041), we get a palindrome (464583141385464).

The spelling of 140441120241423 in words is "one hundred forty trillion, four hundred forty-one billion, one hundred twenty million, two hundred forty-one thousand, four hundred twenty-three".

Divisors: 1 3 46813706747141 140441120241423