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1122401234433 = 32316266684557
BaseRepresentation
bin10000010101010100010…
…100111010111000000001
310222022010001221101101010
4100111110110322320001
5121342134204000213
62215342441431133
7144043102035633
oct20252424727001
93868101841333
101122401234433
113a300a265a86
12161641a9b4a9
1381ac3ab168b
143c478650a53
151e2e2438ac3
hex1055453ae01

1122401234433 has 8 divisors (see below), whose sum is σ = 1561601717568. Its totient is φ = 715734120464.

The previous prime is 1122401234417. The next prime is 1122401234491. The reversal of 1122401234433 is 3344321042211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1122401234433 - 24 = 1122401234417 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1122401234433.

It is not an unprimeable number, because it can be changed into a prime (1122401234333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8133342210 + ... + 8133342347.

It is an arithmetic number, because the mean of its divisors is an integer number (195200214696).

Almost surely, 21122401234433 is an apocalyptic number.

It is an amenable number.

1122401234433 is a deficient number, since it is larger than the sum of its proper divisors (439200483135).

1122401234433 is a wasteful number, since it uses less digits than its factorization.

1122401234433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16266684583.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 1122401234433 its reverse (3344321042211), we get a palindrome (4466722276644).

The spelling of 1122401234433 in words is "one trillion, one hundred twenty-two billion, four hundred one million, two hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 3 23 69 16266684557 48800053671 374133744811 1122401234433