Base | Representation |
---|---|
bin | 10100111010000010… |
… | …11100001011001111 |
3 | 1001222020120022002011 |
4 | 22131001130023033 |
5 | 140441412210210 |
6 | 5053440242051 |
7 | 545102162623 |
oct | 123501341317 |
9 | 31866508064 |
10 | 11224335055 |
11 | 483a93206a |
12 | 2213010327 |
13 | 109b55229b |
14 | 7869c9183 |
15 | 45a603d8a |
hex | 29d05c2cf |
11224335055 has 8 divisors (see below), whose sum is σ = 13525560000. Its totient is φ = 8941896096.
The previous prime is 11224335019. The next prime is 11224335077. The reversal of 11224335055 is 55053342211.
11224335055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11224335055 - 29 = 11224334543 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4695180 + ... + 4697569.
It is an arithmetic number, because the mean of its divisors is an integer number (1690695000).
Almost surely, 211224335055 is an apocalyptic number.
11224335055 is a deficient number, since it is larger than the sum of its proper divisors (2301224945).
11224335055 is an equidigital number, since it uses as much as digits as its factorization.
11224335055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9392993.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 11224335055 its reverse (55053342211), we get a palindrome (66277677266).
The spelling of 11224335055 in words is "eleven billion, two hundred twenty-four million, three hundred thirty-five thousand, fifty-five".
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