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11224400133 = 33741466711
BaseRepresentation
bin10100111010000011…
…01100000100000101
31001222020200121100110
422131001230010011
5140441421301013
65053441503233
7545102553432
oct123501540405
931866617313
1011224400133
11483a976a51
122213041b19
13109b575aab
14786a04b89
1545a6182c3
hex29d06c105

11224400133 has 4 divisors (see below), whose sum is σ = 14965866848. Its totient is φ = 7482933420.

The previous prime is 11224400101. The next prime is 11224400141. The reversal of 11224400133 is 33100442211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11224400133 - 25 = 11224400101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11224400183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1870733353 + ... + 1870733358.

It is an arithmetic number, because the mean of its divisors is an integer number (3741466712).

Almost surely, 211224400133 is an apocalyptic number.

It is an amenable number.

11224400133 is a deficient number, since it is larger than the sum of its proper divisors (3741466715).

11224400133 is an equidigital number, since it uses as much as digits as its factorization.

11224400133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3741466714.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 11224400133 its reverse (33100442211), we get a palindrome (44324842344).

The spelling of 11224400133 in words is "eleven billion, two hundred twenty-four million, four hundred thousand, one hundred thirty-three".

Divisors: 1 3 3741466711 11224400133