Search a number
-
+
11225433 = 34779613
BaseRepresentation
bin101010110100…
…100101011001
3210010022101210
4222310211121
510333203213
61040333333
7164262132
oct52644531
923108353
1011225433
11637791a
123914249
13243058b
1416c2c89
15ebb0c3
hexab4959

11225433 has 8 divisors (see below), whose sum is σ = 15285888. Its totient is φ = 7324304.

The previous prime is 11225419. The next prime is 11225437. The reversal of 11225433 is 33452211.

11225433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11225433 - 214 = 11209049 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11225437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39666 + ... + 39947.

It is an arithmetic number, because the mean of its divisors is an integer number (1910736).

Almost surely, 211225433 is an apocalyptic number.

It is an amenable number.

11225433 is a deficient number, since it is larger than the sum of its proper divisors (4060455).

11225433 is an equidigital number, since it uses as much as digits as its factorization.

11225433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79663.

The product of its digits is 720, while the sum is 21.

The square root of 11225433 is about 3350.4377325955. The cubic root of 11225433 is about 223.9070152436.

Adding to 11225433 its reverse (33452211), we get a palindrome (44677644).

It can be divided in two parts, 1122 and 5433, that added together give a triangular number (6555 = T114).

The spelling of 11225433 in words is "eleven million, two hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 3 47 141 79613 238839 3741811 11225433