Base | Representation |
---|---|
bin | 10000010101111000000… |
… | …010010010110000111011 |
3 | 10222100122211020122210211 |
4 | 100111320002102300323 |
5 | 121344401041100243 |
6 | 2215522122251551 |
7 | 144063665214043 |
oct | 20257002226073 |
9 | 3870584218724 |
10 | 1123000331323 |
11 | 3a3297457382 |
12 | 16178a656bb7 |
13 | 81b8ac52190 |
14 | 3c4d4040723 |
15 | 1e329d28d9d |
hex | 10578092c3b |
1123000331323 has 8 divisors (see below), whose sum is σ = 1280525264928. Its totient is φ = 975638296704.
The previous prime is 1123000331281. The next prime is 1123000331347. The reversal of 1123000331323 is 3231330003211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1123000331323 - 225 = 1122966776891 is a prime.
It is a super-2 number, since 2×11230003313232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1123000331294 and 1123000331303.
It is not an unprimeable number, because it can be changed into a prime (1123000335323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2540724511 + ... + 2540724952.
It is an arithmetic number, because the mean of its divisors is an integer number (160065658116).
Almost surely, 21123000331323 is an apocalyptic number.
1123000331323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1123000331323 is a deficient number, since it is larger than the sum of its proper divisors (157524933605).
1123000331323 is a wasteful number, since it uses less digits than its factorization.
1123000331323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5081449493.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 1123000331323 its reverse (3231330003211), we get a palindrome (4354330334534).
The spelling of 1123000331323 in words is "one trillion, one hundred twenty-three billion, three hundred thirty-one thousand, three hundred twenty-three".
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