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11231100113 = 58391192343
BaseRepresentation
bin10100111010110110…
…01111110011010001
31001222201021222222212
422131123033303101
5141000130200423
65054241241505
7545213530052
oct123533176321
931881258885
1011231100113
114843732822
122215333295
13109ca8058c
1478786a729
1545aedd578
hex29d6cfcd1

11231100113 has 4 divisors (see below), whose sum is σ = 11231350848. Its totient is φ = 11230849380.

The previous prime is 11231100071. The next prime is 11231100149. The reversal of 11231100113 is 31100113211.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11231100113 - 224 = 11214322897 is a prime.

It is a super-2 number, since 2×112311001132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11231100163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37781 + ... + 154562.

It is an arithmetic number, because the mean of its divisors is an integer number (2807837712).

Almost surely, 211231100113 is an apocalyptic number.

It is an amenable number.

11231100113 is a deficient number, since it is larger than the sum of its proper divisors (250735).

11231100113 is an equidigital number, since it uses as much as digits as its factorization.

11231100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 250734.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 11231100113 its reverse (31100113211), we get a palindrome (42331213324).

The spelling of 11231100113 in words is "eleven billion, two hundred thirty-one million, one hundred thousand, one hundred thirteen".

Divisors: 1 58391 192343 11231100113