Base | Representation |
---|---|
bin | 10000010110000000100… |
… | …011101110110001000101 |
3 | 10222101000210021221212002 |
4 | 100112000203232301011 |
5 | 121400144142031001 |
6 | 2215544231035045 |
7 | 144100352440445 |
oct | 20260043566105 |
9 | 3871023257762 |
10 | 1123143314501 |
11 | 3a336013679a |
12 | 16180a50ba85 |
13 | 81bb1765300 |
14 | 3c509020125 |
15 | 1e33766e46b |
hex | 105808eec45 |
1123143314501 has 12 divisors (see below), whose sum is σ = 1216341667008. Its totient is φ = 1036613929104.
The previous prime is 1123143314443. The next prime is 1123143314521. The reversal of 1123143314501 is 1054133413211.
It is not a de Polignac number, because 1123143314501 - 214 = 1123143298117 is a prime.
It is a super-2 number, since 2×11231433145012 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1123143314521) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 897326 + ... + 1746848.
It is an arithmetic number, because the mean of its divisors is an integer number (101361805584).
Almost surely, 21123143314501 is an apocalyptic number.
It is an amenable number.
1123143314501 is a deficient number, since it is larger than the sum of its proper divisors (93198352507).
1123143314501 is an equidigital number, since it uses as much as digits as its factorization.
1123143314501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 857372 (or 857359 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 1123143314501 its reverse (1054133413211), we get a palindrome (2177276727712).
The spelling of 1123143314501 in words is "one trillion, one hundred twenty-three billion, one hundred forty-three million, three hundred fourteen thousand, five hundred one".
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