11231444041 has 4 divisors (see below), whose sum is σ = 11231660032. Its totient is φ = 11231228052.

The previous prime is 11231444033. The next prime is 11231444047. The reversal of 11231444041 is 14044413211.

11231444041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14044413211 = 179 ⋅78460409.

It is a cyclic number.

It is not a de Polignac number, because 11231444041 - 2³ = 11231444033 is a prime.

It is a super-2 number, since 2×11231444041² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11231443997 and 11231444015.

It is not an unprimeable number, because it can be changed into a prime (11231444047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22840 + ... + 151606.

It is an arithmetic number, because the mean of its divisors is an integer number (2807915008).

Almost surely, 2^11231444041 is an apocalyptic number.

It is an amenable number.

11231444041 is a deficient number, since it is larger than the sum of its proper divisors (215991).

11231444041 is an equidigital number, since it uses as much as digits as its factorization.

11231444041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215990.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 11231444041 its reverse (14044413211), we get a palindrome (25275857252).

The spelling of 11231444041 in words is "eleven billion, two hundred thirty-one million, four hundred forty-four thousand, forty-one".