112341224013013 has 4 divisors (see below), whose sum is σ = 115377473310700. Its totient is φ = 109304974715328.

The previous prime is 112341224013001. The next prime is 112341224013061. The reversal of 112341224013013 is 310310422143211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 81187434305649 + 31153789707364 = 9010407^2 + 5581558^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112341224013013 is a prime.

It is a super-2 number, since 2×112341224013013² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112341224413013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1518124648788 + ... + 1518124648861.

It is an arithmetic number, because the mean of its divisors is an integer number (28844368327675).

Almost surely, 2^{112341224013013} is an apocalyptic number.

It is an amenable number.

112341224013013 is a deficient number, since it is larger than the sum of its proper divisors (3036249297687).

112341224013013 is an equidigital number, since it uses as much as digits as its factorization.

112341224013013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3036249297686.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 112341224013013 its reverse (310310422143211), we get a palindrome (422651646156224).

The spelling of 112341224013013 in words is "one hundred twelve trillion, three hundred forty-one billion, two hundred twenty-four million, thirteen thousand, thirteen".