112341341423141 has 4 divisors (see below), whose sum is σ = 112447024718112. Its totient is φ = 112235658128172.

The previous prime is 112341341423111. The next prime is 112341341423183. The reversal of 112341341423141 is 141324143143211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112341341423141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112341341423111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52841645891 + ... + 52841648016.

It is an arithmetic number, because the mean of its divisors is an integer number (28111756179528).

Almost surely, 2^{112341341423141} is an apocalyptic number.

It is an amenable number.

112341341423141 is a deficient number, since it is larger than the sum of its proper divisors (105683294971).

112341341423141 is a wasteful number, since it uses less digits than its factorization.

112341341423141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105683294970.

The product of its digits is 27648, while the sum is 35.

Adding to 112341341423141 its reverse (141324143143211), we get a palindrome (253665484566352).

The spelling of 112341341423141 in words is "one hundred twelve trillion, three hundred forty-one billion, three hundred forty-one million, four hundred twenty-three thousand, one hundred forty-one".