Base | Representation |
---|---|
bin | 11001100010110010010010… |
… | …101000100111001101010001 |
3 | 112201202202100222120020000202 |
4 | 121202302102220213031101 |
5 | 104211101121411322230 |
6 | 1034533010244024545 |
7 | 32443262121262625 |
oct | 3142622250471521 |
9 | 481682328506022 |
10 | 112341624714065 |
11 | 328828a745800a |
12 | 10724686992155 |
13 | 4a8ba011c3746 |
14 | 1da5513bc9185 |
15 | cec3e4317a45 |
hex | 662c92a27351 |
112341624714065 has 8 divisors (see below), whose sum is σ = 134810013868200. Its totient is φ = 89873256963712.
The previous prime is 112341624714049. The next prime is 112341624714091. The reversal of 112341624714065 is 560417426143211.
It can be written as a sum of positive squares in 4 ways, for example, as 23334155335936 + 89007469378129 = 4830544^2 + 9434377^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 112341624714065 - 24 = 112341624714049 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10423877 + ... + 18257613.
It is an arithmetic number, because the mean of its divisors is an integer number (16851251733525).
Almost surely, 2112341624714065 is an apocalyptic number.
It is an amenable number.
112341624714065 is a deficient number, since it is larger than the sum of its proper divisors (22468389154135).
112341624714065 is an equidigital number, since it uses as much as digits as its factorization.
112341624714065 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10701891.
The product of its (nonzero) digits is 967680, while the sum is 47.
The spelling of 112341624714065 in words is "one hundred twelve trillion, three hundred forty-one billion, six hundred twenty-four million, seven hundred fourteen thousand, sixty-five".
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