Base | Representation |
---|---|
bin | 1010001101111010101010… |
… | …0100101001110111001111 |
3 | 1110202222102210120001220211 |
4 | 2203132222210221313033 |
5 | 2433030121002330130 |
6 | 35520530520223251 |
7 | 2236433656515604 |
oct | 243365244516717 |
9 | 43688383501824 |
10 | 11234201214415 |
11 | 364144178a773 |
12 | 131531b30ab27 |
13 | 6364c431a9ba |
14 | 2aba49a326ab |
15 | 1473624c6a2a |
hex | a37aa929dcf |
11234201214415 has 4 divisors (see below), whose sum is σ = 13481041457304. Its totient is φ = 8987360971528.
The previous prime is 11234201214361. The next prime is 11234201214419. The reversal of 11234201214415 is 51441210243211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11234201214415 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11234201214419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1123420121437 + ... + 1123420121446.
It is an arithmetic number, because the mean of its divisors is an integer number (3370260364326).
Almost surely, 211234201214415 is an apocalyptic number.
11234201214415 is a deficient number, since it is larger than the sum of its proper divisors (2246840242889).
11234201214415 is an equidigital number, since it uses as much as digits as its factorization.
11234201214415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2246840242888.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 11234201214415 its reverse (51441210243211), we get a palindrome (62675411457626).
The spelling of 11234201214415 in words is "eleven trillion, two hundred thirty-four billion, two hundred one million, two hundred fourteen thousand, four hundred fifteen".
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