Base | Representation |
---|---|
bin | 11001100010110011000101… |
… | …000111101100100000111001 |
3 | 112201202211120000100201221110 |
4 | 121202303011013230200321 |
5 | 104211104340230114230 |
6 | 1034533230302230533 |
7 | 32443322114605623 |
oct | 3142630507544071 |
9 | 481684500321843 |
10 | 112342471723065 |
11 | 328831a1586451 |
12 | 10724882585449 |
13 | 4a8bb078254bc |
14 | 1da55944adc13 |
15 | cec4438784b0 |
hex | 662cc51ec839 |
112342471723065 has 64 divisors (see below), whose sum is σ = 189345340800000. Its totient is φ = 56721432791808.
The previous prime is 112342471723063. The next prime is 112342471723133. The reversal of 112342471723065 is 560327174243211.
It is not a de Polignac number, because 112342471723065 - 21 = 112342471723063 is a prime.
It is a super-3 number, since 3×1123424717230653 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (112342471723063) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3925436326 + ... + 3925464944.
It is an arithmetic number, because the mean of its divisors is an integer number (2958520950000).
Almost surely, 2112342471723065 is an apocalyptic number.
112342471723065 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
112342471723065 is a deficient number, since it is larger than the sum of its proper divisors (77002869076935).
112342471723065 is a wasteful number, since it uses less digits than its factorization.
112342471723065 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38134.
The product of its (nonzero) digits is 1693440, while the sum is 48.
The spelling of 112342471723065 in words is "one hundred twelve trillion, three hundred forty-two billion, four hundred seventy-one million, seven hundred twenty-three thousand, sixty-five".
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