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11234330000131 = 72229272040819
BaseRepresentation
bin1010001101111011001000…
…1111111011101100000011
31110202222202202220001201011
42203132302033323230003
52433030401440001011
635520551400421351
72236440112261300
oct243366217735403
943688682801634
1011234330000131
1136414a8452347
121315356477857
13636514bcc874
142aba5cb980a7
1514736d965621
hexa37b23fbb03

11234330000131 has 6 divisors (see below), whose sum is σ = 13068506326740. Its totient is φ = 9629425714356.

The previous prime is 11234330000119. The next prime is 11234330000149. The reversal of 11234330000131 is 13100003343211.

It is not a de Polignac number, because 11234330000131 - 219 = 11234329475843 is a prime.

It is a super-2 number, since 2×112343300001312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11234330000161) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 114636020361 + ... + 114636020458.

It is an arithmetic number, because the mean of its divisors is an integer number (2178084387790).

Almost surely, 211234330000131 is an apocalyptic number.

11234330000131 is a deficient number, since it is larger than the sum of its proper divisors (1834176326609).

11234330000131 is an equidigital number, since it uses as much as digits as its factorization.

11234330000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229272040833 (or 229272040826 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 11234330000131 its reverse (13100003343211), we get a palindrome (24334333343342).

The spelling of 11234330000131 in words is "eleven trillion, two hundred thirty-four billion, three hundred thirty million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 7 49 229272040819 1604904285733 11234330000131