Base | Representation |
---|---|
bin | 1010001101111011001000… |
… | …1111111011101100000011 |
3 | 1110202222202202220001201011 |
4 | 2203132302033323230003 |
5 | 2433030401440001011 |
6 | 35520551400421351 |
7 | 2236440112261300 |
oct | 243366217735403 |
9 | 43688682801634 |
10 | 11234330000131 |
11 | 36414a8452347 |
12 | 1315356477857 |
13 | 636514bcc874 |
14 | 2aba5cb980a7 |
15 | 14736d965621 |
hex | a37b23fbb03 |
11234330000131 has 6 divisors (see below), whose sum is σ = 13068506326740. Its totient is φ = 9629425714356.
The previous prime is 11234330000119. The next prime is 11234330000149. The reversal of 11234330000131 is 13100003343211.
It is not a de Polignac number, because 11234330000131 - 219 = 11234329475843 is a prime.
It is a super-2 number, since 2×112343300001312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11234330000161) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 114636020361 + ... + 114636020458.
It is an arithmetic number, because the mean of its divisors is an integer number (2178084387790).
Almost surely, 211234330000131 is an apocalyptic number.
11234330000131 is a deficient number, since it is larger than the sum of its proper divisors (1834176326609).
11234330000131 is an equidigital number, since it uses as much as digits as its factorization.
11234330000131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 229272040833 (or 229272040826 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11234330000131 its reverse (13100003343211), we get a palindrome (24334333343342).
The spelling of 11234330000131 in words is "eleven trillion, two hundred thirty-four billion, three hundred thirty million, one hundred thirty-one", and thus it is an aban number.
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