11234330000130 has 32 divisors (see below), whose sum is σ = 26971603824384. Its totient is φ = 2994797797376.

The previous prime is 11234330000119. The next prime is 11234330000149. The reversal of 11234330000130 is 3100003343211.

It is a junction number, because it is equal to n+sod(n) for n = 11234330000097 and 11234330000106.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63881727 + ... + 64057346.

It is an arithmetic number, because the mean of its divisors is an integer number (842862619512).

Almost surely, 2^{11234330000130} is an apocalyptic number.

11234330000130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11234330000130 is an abundant number, since it is smaller than the sum of its proper divisors (15737273824254).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11234330000130 is a wasteful number, since it uses less digits than its factorization.

11234330000130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 127942010.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 11234330000130 its reverse (3100003343211), we get a palindrome (14334333343341).

The spelling of 11234330000130 in words is "eleven trillion, two hundred thirty-four billion, three hundred thirty million, one hundred thirty", and thus it is an aban number.