1123470002557 has 4 divisors (see below), whose sum is σ = 1283965717216. Its totient is φ = 962974287900.

The previous prime is 1123470002537. The next prime is 1123470002561. The reversal of 1123470002557 is 7552000743211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1123470002557 - 2³⁵ = 1089110264189 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1123470002537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80247857319 + ... + 80247857332.

It is an arithmetic number, because the mean of its divisors is an integer number (320991429304).

Almost surely, 2^{1123470002557} is an apocalyptic number.

It is an amenable number.

1123470002557 is a deficient number, since it is larger than the sum of its proper divisors (160495714659).

1123470002557 is an equidigital number, since it uses as much as digits as its factorization.

1123470002557 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 160495714658.

The product of its (nonzero) digits is 58800, while the sum is 37.

Adding to 1123470002557 its reverse (7552000743211), we get a palindrome (8675470745768).

The spelling of 1123470002557 in words is "one trillion, one hundred twenty-three billion, four hundred seventy million, two thousand, five hundred fifty-seven".