112365004320433 has 4 divisors (see below), whose sum is σ = 112373087566068. Its totient is φ = 112356921074800.

The previous prime is 112365004320431. The next prime is 112365004320493. The reversal of 112365004320433 is 334023400563211.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 42426372683809 + 69938631636624 = 6513553^2 + 8362932^2 .

It is a cyclic number.

It is not a de Polignac number, because 112365004320433 - 2¹ = 112365004320431 is a prime.

It is a super-2 number, since 2×112365004320433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112365004320392 and 112365004320401.

It is not an unprimeable number, because it can be changed into a prime (112365004320431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4041601966 + ... + 4041629767.

It is an arithmetic number, because the mean of its divisors is an integer number (28093271891517).

Almost surely, 2^{112365004320433} is an apocalyptic number.

It is an amenable number.

112365004320433 is a deficient number, since it is larger than the sum of its proper divisors (8083245635).

112365004320433 is an equidigital number, since it uses as much as digits as its factorization.

112365004320433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8083245634.

The product of its (nonzero) digits is 155520, while the sum is 37.

Adding to 112365004320433 its reverse (334023400563211), we get a palindrome (446388404883644).

The spelling of 112365004320433 in words is "one hundred twelve trillion, three hundred sixty-five billion, four million, three hundred twenty thousand, four hundred thirty-three".