Base | Representation |
---|---|
bin | 11001100011101010100011… |
… | …111000001100100110111011 |
3 | 112201222112022200021022110212 |
4 | 121203222203320030212323 |
5 | 104213043341122213420 |
6 | 1035020441433301335 |
7 | 32450531265040661 |
oct | 3143524370144673 |
9 | 481875280238425 |
10 | 112402043554235 |
11 | 328a64912a8976 |
12 | 10734328b6484b |
13 | 4a9460c65a746 |
14 | 1da8406148c31 |
15 | cedc7d7013c5 |
hex | 663aa3e0c9bb |
112402043554235 has 32 divisors (see below), whose sum is σ = 143331814738944. Its totient is φ = 84326910976000.
The previous prime is 112402043554217. The next prime is 112402043554247. The reversal of 112402043554235 is 532455340204211.
It is not a de Polignac number, because 112402043554235 - 214 = 112402043537851 is a prime.
It is a super-2 number, since 2×1124020435542352 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 112402043554192 and 112402043554201.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 556921190 + ... + 557122980.
It is an arithmetic number, because the mean of its divisors is an integer number (4479119210592).
Almost surely, 2112402043554235 is an apocalyptic number.
112402043554235 is a deficient number, since it is larger than the sum of its proper divisors (30929771184709).
112402043554235 is a wasteful number, since it uses less digits than its factorization.
112402043554235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 225415.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 112402043554235 its reverse (532455340204211), we get a palindrome (644857383758446).
The spelling of 112402043554235 in words is "one hundred twelve trillion, four hundred two billion, forty-three million, five hundred fifty-four thousand, two hundred thirty-five".
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