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112421131323 = 337473710441
BaseRepresentation
bin110100010110011010…
…0100101010000111011
3101202011211012012011120
41220230310211100323
53320214302200243
6123351235000323
711056620564234
oct1505464452073
9352154165146
10112421131323
114374a885996
12199557390a3
13a7a7ca3ba7
14562698408b
152dce944c83
hex1a2cd2543b

112421131323 has 4 divisors (see below), whose sum is σ = 149894841768. Its totient is φ = 74947420880.

The previous prime is 112421131321. The next prime is 112421131399. The reversal of 112421131323 is 323131124211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112421131323 - 21 = 112421131321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112421131293 and 112421131302.

It is not an unprimeable number, because it can be changed into a prime (112421131321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18736855218 + ... + 18736855223.

It is an arithmetic number, because the mean of its divisors is an integer number (37473710442).

Almost surely, 2112421131323 is an apocalyptic number.

112421131323 is a deficient number, since it is larger than the sum of its proper divisors (37473710445).

112421131323 is an equidigital number, since it uses as much as digits as its factorization.

112421131323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37473710444.

The product of its digits is 864, while the sum is 24.

Adding to 112421131323 its reverse (323131124211), we get a palindrome (435552255534).

The spelling of 112421131323 in words is "one hundred twelve billion, four hundred twenty-one million, one hundred thirty-one thousand, three hundred twenty-three".

Divisors: 1 3 37473710441 112421131323