Base | Representation |
---|---|
bin | 10100111100001100… |
… | …11110110000001111 |
3 | 1002000111121210112211 |
4 | 22132012132300033 |
5 | 141011030333201 |
6 | 5055324211251 |
7 | 545412052126 |
oct | 123606366017 |
9 | 32014553484 |
10 | 11242433551 |
11 | 484a0737a8 |
12 | 2219099b27 |
13 | 10a221b05b |
14 | 78917aabd |
15 | 45becb651 |
hex | 29e19ec0f |
11242433551 has 8 divisors (see below), whose sum is σ = 11835303680. Its totient is φ = 10649679768.
The previous prime is 11242433533. The next prime is 11242433561. The reversal of 11242433551 is 15533424211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11242433551 - 25 = 11242433519 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11242433561) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 227290 + ... + 272296.
It is an arithmetic number, because the mean of its divisors is an integer number (1479412960).
Almost surely, 211242433551 is an apocalyptic number.
11242433551 is a deficient number, since it is larger than the sum of its proper divisors (592870129).
11242433551 is a wasteful number, since it uses less digits than its factorization.
11242433551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58173.
The product of its digits is 14400, while the sum is 31.
Adding to 11242433551 its reverse (15533424211), we get a palindrome (26775857762).
The spelling of 11242433551 in words is "eleven billion, two hundred forty-two million, four hundred thirty-three thousand, five hundred fifty-one".
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