Base | Representation |
---|---|
bin | 1010001110011111101100… |
… | …1011010000000010100101 |
3 | 1110210221002200121200010010 |
4 | 2203213323023100002211 |
5 | 2433211001210203013 |
6 | 35525253240520433 |
7 | 2240235233211225 |
oct | 243477313200245 |
9 | 43727080550103 |
10 | 11244143444133 |
11 | 3645683927046 |
12 | 1317234a80119 |
13 | 63741a05c072 |
14 | 2ac310238085 |
15 | 1477452727c3 |
hex | a39fb2d00a5 |
11244143444133 has 16 divisors (see below), whose sum is σ = 15204623616000. Its totient is φ = 7389897155760.
The previous prime is 11244143444123. The next prime is 11244143444147. The reversal of 11244143444133 is 33144434144211.
It is not a de Polignac number, because 11244143444133 - 212 = 11244143440037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11244143444091 and 11244143444100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11244143444123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 340168 + ... + 4754366.
It is an arithmetic number, because the mean of its divisors is an integer number (950288976000).
Almost surely, 211244143444133 is an apocalyptic number.
It is an amenable number.
11244143444133 is a deficient number, since it is larger than the sum of its proper divisors (3960480171867).
11244143444133 is a wasteful number, since it uses less digits than its factorization.
11244143444133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4426232.
The product of its digits is 221184, while the sum is 39.
Adding to 11244143444133 its reverse (33144434144211), we get a palindrome (44388577588344).
The spelling of 11244143444133 in words is "eleven trillion, two hundred forty-four billion, one hundred forty-three million, four hundred forty-four thousand, one hundred thirty-three".
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