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11244143444133 = 371119594414199
BaseRepresentation
bin1010001110011111101100…
…1011010000000010100101
31110210221002200121200010010
42203213323023100002211
52433211001210203013
635525253240520433
72240235233211225
oct243477313200245
943727080550103
1011244143444133
113645683927046
121317234a80119
1363741a05c072
142ac310238085
151477452727c3
hexa39fb2d00a5

11244143444133 has 16 divisors (see below), whose sum is σ = 15204623616000. Its totient is φ = 7389897155760.

The previous prime is 11244143444123. The next prime is 11244143444147. The reversal of 11244143444133 is 33144434144211.

It is not a de Polignac number, because 11244143444133 - 212 = 11244143440037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11244143444091 and 11244143444100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11244143444123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 340168 + ... + 4754366.

It is an arithmetic number, because the mean of its divisors is an integer number (950288976000).

Almost surely, 211244143444133 is an apocalyptic number.

It is an amenable number.

11244143444133 is a deficient number, since it is larger than the sum of its proper divisors (3960480171867).

11244143444133 is a wasteful number, since it uses less digits than its factorization.

11244143444133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4426232.

The product of its digits is 221184, while the sum is 39.

Adding to 11244143444133 its reverse (33144434144211), we get a palindrome (44388577588344).

The spelling of 11244143444133 in words is "eleven trillion, two hundred forty-four billion, one hundred forty-three million, four hundred forty-four thousand, one hundred thirty-three".

Divisors: 1 3 71 213 11959 35877 849089 2547267 4414199 13242597 313408129 940224387 52789405841 158368217523 3748047814711 11244143444133