Base | Representation |
---|---|
bin | 10000010111001101111… |
… | …110010000011111010011 |
3 | 10222111101022012210211100 |
4 | 100113031332100133103 |
5 | 121410324140122003 |
6 | 2220321144515443 |
7 | 144144503161065 |
oct | 20271576203723 |
9 | 3874338183740 |
10 | 1124442114003 |
11 | 3a396729400a |
12 | 161b1147bb83 |
13 | 8205a86ca20 |
14 | 3c5cd70b735 |
15 | 1e3b16c3ba3 |
hex | 105cdf907d3 |
1124442114003 has 48 divisors (see below), whose sum is σ = 1763331687936. Its totient is φ = 686369557440.
The previous prime is 1124442114001. The next prime is 1124442114007. The reversal of 1124442114003 is 3004112444211.
1124442114003 is a `hidden beast` number, since 1 + 1 + 2 + 4 + 44 + 211 + 400 + 3 = 666.
It is not a de Polignac number, because 1124442114003 - 21 = 1124442114001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1124442114001) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7119376 + ... + 7275602.
It is an arithmetic number, because the mean of its divisors is an integer number (36736076832).
Almost surely, 21124442114003 is an apocalyptic number.
1124442114003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1124442114003 is a deficient number, since it is larger than the sum of its proper divisors (638889573933).
1124442114003 is a wasteful number, since it uses less digits than its factorization.
1124442114003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156744 (or 156741 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 1124442114003 its reverse (3004112444211), we get a palindrome (4128554558214).
The spelling of 1124442114003 in words is "one trillion, one hundred twenty-four billion, four hundred forty-two million, one hundred fourteen thousand, three".
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