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112500013133 = 491229124263
BaseRepresentation
bin110100011000110000…
…1011111100001001101
3101202101022121210200002
41220301201133201031
53320400000410013
6123403133414045
711061566222324
oct1506141374115
9352338553602
10112500013133
1143790362a72
121997803a325
13a7bb432311
1456332390bb
152dd6827358
hex1a3185f84d

112500013133 has 4 divisors (see below), whose sum is σ = 112729137888. Its totient is φ = 112270888380.

The previous prime is 112500013103. The next prime is 112500013139. The reversal of 112500013133 is 331310005211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112500013133 - 222 = 112495818829 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112500013139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114561641 + ... + 114562622.

It is an arithmetic number, because the mean of its divisors is an integer number (28182284472).

Almost surely, 2112500013133 is an apocalyptic number.

It is an amenable number.

112500013133 is a deficient number, since it is larger than the sum of its proper divisors (229124755).

112500013133 is an equidigital number, since it uses as much as digits as its factorization.

112500013133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 229124754.

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 112500013133 its reverse (331310005211), we get a palindrome (443810018344).

The spelling of 112500013133 in words is "one hundred twelve billion, five hundred million, thirteen thousand, one hundred thirty-three".

Divisors: 1 491 229124263 112500013133