Base | Representation |
---|---|
bin | 10100111101010001… |
… | …10001100110011010 |
3 | 1002001010112112122011 |
4 | 22132220301212122 |
5 | 141020331024032 |
6 | 5100245020134 |
7 | 545551344244 |
oct | 123650614632 |
9 | 32033475564 |
10 | 11251423642 |
11 | 4854154128 |
12 | 22200b464a |
13 | 10a4048034 |
14 | 78a43b094 |
15 | 45cba5247 |
hex | 29ea3199a |
11251423642 has 4 divisors (see below), whose sum is σ = 16877135466. Its totient is φ = 5625711820.
The previous prime is 11251423637. The next prime is 11251423691. The reversal of 11251423642 is 24632415211.
11251423642 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10706247841 + 545175801 = 103471^2 + 23349^2 .
It is a super-3 number, since 3×112514236423 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2812855909 + ... + 2812855912.
Almost surely, 211251423642 is an apocalyptic number.
11251423642 is a deficient number, since it is larger than the sum of its proper divisors (5625711824).
11251423642 is an equidigital number, since it uses as much as digits as its factorization.
11251423642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5625711823.
The product of its digits is 11520, while the sum is 31.
Adding to 11251423642 its reverse (24632415211), we get a palindrome (35883838853).
The spelling of 11251423642 in words is "eleven billion, two hundred fifty-one million, four hundred twenty-three thousand, six hundred forty-two".
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