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11252214035 = 514927155733
BaseRepresentation
bin10100111101010111…
…10010100100010011
31002001012000200211222
422132223302210103
5141021031322120
65100313555255
7545561145506
oct123653624423
932035020758
1011252214035
114854643a47
122220415b2b
1310a4263a1a
1478a5a513d
1545ccae525
hex29eaf2913

11252214035 has 16 divisors (see below), whose sum is σ = 13643683200. Its totient is φ = 8908202880.

The previous prime is 11252214007. The next prime is 11252214037. The reversal of 11252214035 is 53041225211.

It is not a de Polignac number, because 11252214035 - 216 = 11252148499 is a prime.

It is a super-2 number, since 2×112522140352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11252213995 and 11252214013.

It is not an unprimeable number, because it can be changed into a prime (11252214037) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 174029 + ... + 229761.

It is an arithmetic number, because the mean of its divisors is an integer number (852730200).

Almost surely, 211252214035 is an apocalyptic number.

11252214035 is a deficient number, since it is larger than the sum of its proper divisors (2391469165).

11252214035 is a wasteful number, since it uses less digits than its factorization.

11252214035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56158.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 11252214035 its reverse (53041225211), we get a palindrome (64293439246).

The spelling of 11252214035 in words is "eleven billion, two hundred fifty-two million, two hundred fourteen thousand, thirty-five".

Divisors: 1 5 149 271 745 1355 40379 55733 201895 278665 8304217 15103643 41521085 75518215 2250442807 11252214035