1125304335 has 12 divisors (see below), whose sum is σ = 1950527592. Its totient is φ = 600162288.

The previous prime is 1125304333. The next prime is 1125304357. The reversal of 1125304335 is 5334035211.

1125304335 is a `hidden beast` number, since 1 + 1 + 25 + 304 + 335 = 666.

It is not a de Polignac number, because 1125304335 - 2¹ = 1125304333 is a prime.

It is a super-3 number, since 3×1125304335³ (a number of 28 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1125304299 and 1125304308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1125304333) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12503337 + ... + 12503426.

It is an arithmetic number, because the mean of its divisors is an integer number (162543966).

Almost surely, 2^1125304335 is an apocalyptic number.

1125304335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1125304335 is a deficient number, since it is larger than the sum of its proper divisors (825223257).

1125304335 is a wasteful number, since it uses less digits than its factorization.

1125304335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25006774 (or 25006771 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

The square root of 1125304335 is about 33545.5561140369. The cubic root of 1125304335 is about 1040.1356871164.

Adding to 1125304335 its reverse (5334035211), we get a palindrome (6459339546).

The spelling of 1125304335 in words is "one billion, one hundred twenty-five million, three hundred four thousand, three hundred thirty-five".