Base | Representation |
---|---|
bin | 1010001111000010101101… |
… | …0100111100001000101011 |
3 | 1110211211100122012101220021 |
4 | 2203300223110330020223 |
5 | 2433334223023200003 |
6 | 35533445551541311 |
7 | 2241020146062250 |
oct | 243605324741053 |
9 | 43754318171807 |
10 | 11253541225003 |
11 | 36496667079a0 |
12 | 131901822a837 |
13 | 63828705484c |
14 | 2ac9623d7427 |
15 | 147ae53252bd |
hex | a3c2b53c22b |
11253541225003 has 16 divisors (see below), whose sum is σ = 14188033889280. Its totient is φ = 8670465144000.
The previous prime is 11253541224971. The next prime is 11253541225007. The reversal of 11253541225003 is 30052214535211.
It is not a de Polignac number, because 11253541225003 - 25 = 11253541224971 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11253541225003.
It is not an unprimeable number, because it can be changed into a prime (11253541225007) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 821059923 + ... + 821073628.
It is an arithmetic number, because the mean of its divisors is an integer number (886752118080).
Almost surely, 211253541225003 is an apocalyptic number.
11253541225003 is a deficient number, since it is larger than the sum of its proper divisors (2934492664277).
11253541225003 is a wasteful number, since it uses less digits than its factorization.
11253541225003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1642133658.
The product of its (nonzero) digits is 36000, while the sum is 34.
It can be divided in two parts, 11253541 and 225003, that added together give a square (11478544 = 33882).
The spelling of 11253541225003 in words is "eleven trillion, two hundred fifty-three billion, five hundred forty-one million, two hundred twenty-five thousand, three".
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