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1125402220033 = 71312367057363
BaseRepresentation
bin10000011000000111001…
…100110001011000000001
310222120212012211020200221
4100120013030301120001
5121414310432020113
62221000323143041
7144210342015040
oct20300714613001
93876765736627
101125402220033
113a430a239973
1216213ab14a81
138218174c6c0
143c681032557
151e41ab2498d
hex10607331601

1125402220033 has 8 divisors (see below), whose sum is σ = 1385110424768. Its totient is φ = 890428130064.

The previous prime is 1125402220027. The next prime is 1125402220043. The reversal of 1125402220033 is 3300222045211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1125402220033 - 237 = 987963266561 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1125402220043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6183528591 + ... + 6183528772.

It is an arithmetic number, because the mean of its divisors is an integer number (173138803096).

Almost surely, 21125402220033 is an apocalyptic number.

1125402220033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1125402220033 is a deficient number, since it is larger than the sum of its proper divisors (259708204735).

1125402220033 is a wasteful number, since it uses less digits than its factorization.

1125402220033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12367057383.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 1125402220033 its reverse (3300222045211), we get a palindrome (4425624265244).

The spelling of 1125402220033 in words is "one trillion, one hundred twenty-five billion, four hundred two million, two hundred twenty thousand, thirty-three".

Divisors: 1 7 13 91 12367057363 86569401541 160771745719 1125402220033