Base | Representation |
---|---|
bin | 10100111111001001… |
… | …01000010111000001 |
3 | 1002002020001201100120 |
4 | 22133210220113001 |
5 | 141033340130213 |
6 | 5102005210453 |
7 | 546131615061 |
oct | 123744502701 |
9 | 32066051316 |
10 | 11267114433 |
11 | 4861aa0923 |
12 | 2225400a29 |
13 | 10a737cc23 |
14 | 78c5633a1 |
15 | 45e254423 |
hex | 29f9285c1 |
11267114433 has 8 divisors (see below), whose sum is σ = 15342453888. Its totient is φ = 7351592304.
The previous prime is 11267114389. The next prime is 11267114447. The reversal of 11267114433 is 33441176211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11267114433 - 213 = 11267106241 is a prime.
It is a super-2 number, since 2×112671144332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11267114394 and 11267114403.
It is not an unprimeable number, because it can be changed into a prime (11267114473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39954166 + ... + 39954447.
It is an arithmetic number, because the mean of its divisors is an integer number (1917806736).
Almost surely, 211267114433 is an apocalyptic number.
It is an amenable number.
11267114433 is a deficient number, since it is larger than the sum of its proper divisors (4075339455).
11267114433 is an equidigital number, since it uses as much as digits as its factorization.
11267114433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79908663.
The product of its digits is 12096, while the sum is 33.
The spelling of 11267114433 in words is "eleven billion, two hundred sixty-seven million, one hundred fourteen thousand, four hundred thirty-three".
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