Base | Representation |
---|---|
bin | 11001101000101110101101… |
… | …001000110101101001011011 |
3 | 112210012210200201102211010120 |
4 | 121220232231020311221123 |
5 | 104234244141330400210 |
6 | 1035444402111444323 |
7 | 32514632240535525 |
oct | 3150565510655133 |
9 | 483183621384116 |
10 | 112750091262555 |
11 | 32a2005514661a |
12 | 1078b8815266a3 |
13 | 4abb398916c96 |
14 | 1dbb1c25c0a15 |
15 | d07d4e168270 |
hex | 668bad235a5b |
112750091262555 has 32 divisors (see below), whose sum is σ = 180802930828800. Its totient is φ = 59999269853952.
The previous prime is 112750091262551. The next prime is 112750091262593. The reversal of 112750091262555 is 555262190057211.
It is not a de Polignac number, because 112750091262555 - 22 = 112750091262551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112750091262498 and 112750091262507.
It is not an unprimeable number, because it can be changed into a prime (112750091262551) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7403826 + ... + 16742664.
It is an arithmetic number, because the mean of its divisors is an integer number (5650091588400).
Almost surely, 2112750091262555 is an apocalyptic number.
112750091262555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
112750091262555 is a deficient number, since it is larger than the sum of its proper divisors (68052839566245).
112750091262555 is an equidigital number, since it uses as much as digits as its factorization.
112750091262555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9340643.
The product of its (nonzero) digits is 1890000, while the sum is 51.
The spelling of 112750091262555 in words is "one hundred twelve trillion, seven hundred fifty billion, ninety-one million, two hundred sixty-two thousand, five hundred fifty-five".
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