Base | Representation |
---|---|
bin | 110100100111101100… |
… | …1000111100101100001 |
3 | 101210200020120101212020 |
4 | 1221033121013211201 |
5 | 3322411242300213 |
6 | 123524554252053 |
7 | 11110162536345 |
oct | 1511731074541 |
9 | 353606511766 |
10 | 113001134433 |
11 | 43a18215900 |
12 | 19a97a27029 |
13 | a86b1ba8b5 |
14 | 567da03625 |
15 | 2e15812923 |
hex | 1a4f647961 |
113001134433 has 24 divisors (see below), whose sum is σ = 167605829664. Its totient is φ = 67660391040.
The previous prime is 113001134429. The next prime is 113001134461. The reversal of 113001134433 is 334431100311.
It is not a de Polignac number, because 113001134433 - 22 = 113001134429 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (113001134833) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1845160 + ... + 1905417.
It is an arithmetic number, because the mean of its divisors is an integer number (6983576236).
Almost surely, 2113001134433 is an apocalyptic number.
It is an amenable number.
113001134433 is a deficient number, since it is larger than the sum of its proper divisors (54604695231).
113001134433 is a wasteful number, since it uses less digits than its factorization.
113001134433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3750685 (or 3750674 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 113001134433 its reverse (334431100311), we get a palindrome (447432234744).
The spelling of 113001134433 in words is "one hundred thirteen billion, one million, one hundred thirty-four thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •