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113001301465 = 51310691626269
BaseRepresentation
bin110100100111101100…
…1110000010111011001
3101210200020212212222121
41221033121300113121
53322411313121330
6123525002021241
711110164133333
oct1511731602731
9353606785877
10113001301465
1143a1831a348
1219a97aa7821
13a86b248930
14567da48453
152e1584717a
hex1a4f6705d9

113001301465 has 16 divisors (see below), whose sum is σ = 146169147600. Its totient is φ = 83369002752.

The previous prime is 113001301451. The next prime is 113001301471. The reversal of 113001301465 is 564103100311.

It can be written as a sum of positive squares in 8 ways, for example, as 2056350409 + 110944951056 = 45347^2 + 333084^2 .

It is a cyclic number.

It is not a de Polignac number, because 113001301465 - 25 = 113001301433 is a prime.

It is a super-2 number, since 2×1130013014652 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 743650 + ... + 882619.

It is an arithmetic number, because the mean of its divisors is an integer number (9135571725).

Almost surely, 2113001301465 is an apocalyptic number.

It is an amenable number.

113001301465 is a deficient number, since it is larger than the sum of its proper divisors (33167846135).

113001301465 is a wasteful number, since it uses less digits than its factorization.

113001301465 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1627356.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 113001301465 its reverse (564103100311), we get a palindrome (677104401776).

The spelling of 113001301465 in words is "one hundred thirteen billion, one million, three hundred one thousand, four hundred sixty-five".

Divisors: 1 5 13 65 1069 5345 13897 69485 1626269 8131345 21141497 105707485 1738481561 8692407805 22600260293 113001301465