11300211133 has 4 divisors (see below), whose sum is σ = 11353766848. Its totient is φ = 11246655420.

The previous prime is 11300211077. The next prime is 11300211157. The reversal of 11300211133 is 33111200311.

11300211133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33111200311 = 7 ⋅4730171473.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11300211133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11300211193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26777541 + ... + 26777962.

It is an arithmetic number, because the mean of its divisors is an integer number (2838441712).

Almost surely, 2^11300211133 is an apocalyptic number.

It is an amenable number.

11300211133 is a deficient number, since it is larger than the sum of its proper divisors (53555715).

11300211133 is an equidigital number, since it uses as much as digits as its factorization.

11300211133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53555714.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11300211133 its reverse (33111200311), we get a palindrome (44411411444).

The spelling of 11300211133 in words is "eleven billion, three hundred million, two hundred eleven thousand, one hundred thirty-three".