Base | Representation |
---|---|
bin | 10000011100011010100… |
… | …011110101101010010101 |
3 | 11000000210011202110012212 |
4 | 100130122203311222111 |
5 | 122003241113020201 |
6 | 2223042553123205 |
7 | 144432666346064 |
oct | 20343243655225 |
9 | 4000704673185 |
10 | 1130022001301 |
11 | 3a626aa61a16 |
12 | 16300a0b9505 |
13 | 827398a469b |
14 | 3c99c7dc1db |
15 | 1e5db4c3abb |
hex | 1071a8f5a95 |
1130022001301 has 4 divisors (see below), whose sum is σ = 1148546952204. Its totient is φ = 1111497050400.
The previous prime is 1130022001279. The next prime is 1130022001309. The reversal of 1130022001301 is 1031002200311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 65844073201 + 1064177928100 = 256601^2 + 1031590^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130022001301 - 222 = 1130017806997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1130022001309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9262475360 + ... + 9262475481.
It is an arithmetic number, because the mean of its divisors is an integer number (287136738051).
Almost surely, 21130022001301 is an apocalyptic number.
It is an amenable number.
1130022001301 is a deficient number, since it is larger than the sum of its proper divisors (18524950903).
1130022001301 is an equidigital number, since it uses as much as digits as its factorization.
1130022001301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18524950902.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 1130022001301 its reverse (1031002200311), we get a palindrome (2161024201612).
The spelling of 1130022001301 in words is "one trillion, one hundred thirty billion, twenty-two million, one thousand, three hundred one".
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