1130032002493 has 4 divisors (see below), whose sum is σ = 1130544956128. Its totient is φ = 1129519048860.

The previous prime is 1130032002467. The next prime is 1130032002521. The reversal of 1130032002493 is 3942002300311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1130032002493 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130032002293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 256473513 + ... + 256477918.

It is an arithmetic number, because the mean of its divisors is an integer number (282636239032).

Almost surely, 2^{1130032002493} is an apocalyptic number.

It is an amenable number.

1130032002493 is a deficient number, since it is larger than the sum of its proper divisors (512953635).

1130032002493 is an equidigital number, since it uses as much as digits as its factorization.

1130032002493 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 512953634.

The product of its (nonzero) digits is 3888, while the sum is 28.

The spelling of 1130032002493 in words is "one trillion, one hundred thirty billion, thirty-two million, two thousand, four hundred ninety-three".