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11300404303 = 55764731357
BaseRepresentation
bin10101000011000111…
…00111110001001111
31002011112201000110201
422201203213301033
5141120400414203
65105154514331
7550014565066
oct124143476117
932145630421
1011300404303
114879869011
1222345959a7
1310b1237486
14792b4b1dd
1546212ce1d
hex2a18e7c4f

11300404303 has 8 divisors (see below), whose sum is σ = 11338551072. Its totient is φ = 11262322656.

The previous prime is 11300404279. The next prime is 11300404319. The reversal of 11300404303 is 30340400311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11300404303 is a prime.

It is a super-2 number, since 2×113004043032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11300401303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 344701 + ... + 376057.

It is an arithmetic number, because the mean of its divisors is an integer number (1417318884).

Almost surely, 211300404303 is an apocalyptic number.

11300404303 is a deficient number, since it is larger than the sum of its proper divisors (38146769).

11300404303 is an equidigital number, since it uses as much as digits as its factorization.

11300404303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32561.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 11300404303 its reverse (30340400311), we get a palindrome (41640804614).

The spelling of 11300404303 in words is "eleven billion, three hundred million, four hundred four thousand, three hundred three".

Divisors: 1 557 647 31357 360379 17465849 20287979 11300404303