Base | Representation |
---|---|
bin | 10000011100011011101… |
… | …110001110001101100001 |
3 | 11000000211112110010002220 |
4 | 100130123232032031201 |
5 | 122003311111004023 |
6 | 2223044531101253 |
7 | 144433324161102 |
oct | 20343356161541 |
9 | 4000745403086 |
10 | 1130041500513 |
11 | 3a627aa6aa72 |
12 | 163014741829 |
13 | 82740940b93 |
14 | 3c9a12363a9 |
15 | 1e5dd0763e3 |
hex | 1071bb8e361 |
1130041500513 has 4 divisors (see below), whose sum is σ = 1506722000688. Its totient is φ = 753361000340.
The previous prime is 1130041500487. The next prime is 1130041500521. The reversal of 1130041500513 is 3150051400311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1130041500513 - 28 = 1130041500257 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1130041500593) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188340250083 + ... + 188340250088.
It is an arithmetic number, because the mean of its divisors is an integer number (376680500172).
Almost surely, 21130041500513 is an apocalyptic number.
It is an amenable number.
1130041500513 is a deficient number, since it is larger than the sum of its proper divisors (376680500175).
1130041500513 is an equidigital number, since it uses as much as digits as its factorization.
1130041500513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 376680500174.
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 1130041500513 its reverse (3150051400311), we get a palindrome (4280092900824).
The spelling of 1130041500513 in words is "one trillion, one hundred thirty billion, forty-one million, five hundred thousand, five hundred thirteen".
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