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11300420043 = 321147251673
BaseRepresentation
bin10101000011000111…
…01011100111001011
31002011112201211001200
422201203223213023
5141120401420133
65105155115243
7550014662013
oct124143534713
932145654050
1011300420043
114879879920
1222345a2b23
1310b12416a3
14792b52c43
15462132913
hex2a18eb9cb

11300420043 has 36 divisors (see below), whose sum is σ = 18194002008. Its totient is φ = 6702891840.

The previous prime is 11300420039. The next prime is 11300420063. The reversal of 11300420043 is 34002400311.

It is not a de Polignac number, because 11300420043 - 22 = 11300420039 is a prime.

It is a super-2 number, since 2×113004200432 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11300419998 and 11300420025.

It is not an unprimeable number, because it can be changed into a prime (11300420003) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 192855 + ... + 244527.

Almost surely, 211300420043 is an apocalyptic number.

11300420043 is a deficient number, since it is larger than the sum of its proper divisors (6893581965).

11300420043 is a wasteful number, since it uses less digits than its factorization.

11300420043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51784 (or 51734 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 18.

Adding to 11300420043 its reverse (34002400311), we get a palindrome (45302820354).

The spelling of 11300420043 in words is "eleven billion, three hundred million, four hundred twenty thousand, forty-three".

Divisors: 1 3 9 11 33 47 99 141 423 517 1551 2209 4653 6627 19881 24299 51673 72897 155019 218691 465057 568403 1705209 2428631 5115627 7285893 21857679 26714941 80144823 114145657 240434469 342436971 1027310913 1255602227 3766806681 11300420043