Base | Representation |
---|---|
bin | 1010010001110001011011… |
… | …1010101010010011001111 |
3 | 1111000022102022222101121020 |
4 | 2210130112322222103033 |
5 | 2440121302004312033 |
6 | 40011204013005223 |
7 | 2244300344212035 |
oct | 244342672522317 |
9 | 44008368871536 |
10 | 11300443432143 |
11 | 3667544796358 |
12 | 1326127783813 |
13 | 63c820090038 |
14 | 2b0d31546555 |
15 | 148e3cc5a6b3 |
hex | a4716eaa4cf |
11300443432143 has 16 divisors (see below), whose sum is σ = 15076561685760. Its totient is φ = 7528978429056.
The previous prime is 11300443432123. The next prime is 11300443432181. The reversal of 11300443432143 is 34123434400311.
It is not a de Polignac number, because 11300443432143 - 25 = 11300443432111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11300443432123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33700596 + ... + 34034262.
It is an arithmetic number, because the mean of its divisors is an integer number (942285105360).
Almost surely, 211300443432143 is an apocalyptic number.
11300443432143 is a deficient number, since it is larger than the sum of its proper divisors (3776118253617).
11300443432143 is a wasteful number, since it uses less digits than its factorization.
11300443432143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 340606.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 11300443432143 its reverse (34123434400311), we get a palindrome (45423877832454).
The spelling of 11300443432143 in words is "eleven trillion, three hundred billion, four hundred forty-three million, four hundred thirty-two thousand, one hundred forty-three".
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