Base | Representation |
---|---|
bin | 10000011100011100011… |
… | …010101011001101100010 |
3 | 11000000212100101011011222 |
4 | 100130130122223031202 |
5 | 122003322101404014 |
6 | 2223050024535042 |
7 | 144433525214156 |
oct | 20343432531542 |
9 | 4000770334158 |
10 | 1130053153634 |
11 | 3a62865aa149 |
12 | 163018621482 |
13 | 82743191012 |
14 | 3c9a29cb066 |
15 | 1e5de0c908e |
hex | 1071c6ab362 |
1130053153634 has 4 divisors (see below), whose sum is σ = 1695079730454. Its totient is φ = 565026576816.
The previous prime is 1130053153633. The next prime is 1130053153679. The reversal of 1130053153634 is 4363513500311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 795847762609 + 334205391025 = 892103^2 + 578105^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1130053153594 and 1130053153603.
It is not an unprimeable number, because it can be changed into a prime (1130053153633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282513288407 + ... + 282513288410.
Almost surely, 21130053153634 is an apocalyptic number.
1130053153634 is a deficient number, since it is larger than the sum of its proper divisors (565026576820).
1130053153634 is an equidigital number, since it uses as much as digits as its factorization.
1130053153634 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 565026576819.
The product of its (nonzero) digits is 48600, while the sum is 35.
Adding to 1130053153634 its reverse (4363513500311), we get a palindrome (5493566653945).
The spelling of 1130053153634 in words is "one trillion, one hundred thirty billion, fifty-three million, one hundred fifty-three thousand, six hundred thirty-four".
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