113007484700311 has 4 divisors (see below), whose sum is σ = 113007507165000. Its totient is φ = 113007462235624.

The previous prime is 113007484700267. The next prime is 113007484700387.

113007484700311 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113007484700311 - 2²⁵ = 113007451145879 is a prime.

It is a super-4 number, since 4×113007484700311⁴ (a number of 57 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113007484700111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175065 + ... + 15034813.

It is an arithmetic number, because the mean of its divisors is an integer number (28251876791250).

Almost surely, 2^{113007484700311} is an apocalyptic number.

113007484700311 is a deficient number, since it is larger than the sum of its proper divisors (22464689).

113007484700311 is an equidigital number, since it uses as much as digits as its factorization.

113007484700311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22464688.

The product of its (nonzero) digits is 56448, while the sum is 40.

The spelling of 113007484700311 in words is "one hundred thirteen trillion, seven billion, four hundred eighty-four million, seven hundred thousand, three hundred eleven".