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11301020131999 = 13869309240923
BaseRepresentation
bin1010010001110011100101…
…0010100110001010011111
31111000100220112010210002011
42210130321102212022133
52440123442123210444
640011341133412051
72244320546115523
oct244347122461237
944010815123064
1011301020131999
11366781027a504
12132626893a027
1363c8b26bb360
142b0d87d85d83
15148e736c4734
hexa47394a629f

11301020131999 has 4 divisors (see below), whose sum is σ = 12170329372936. Its totient is φ = 10431710891064.

The previous prime is 11301020131981. The next prime is 11301020132033. The reversal of 11301020131999 is 99913102010311.

11301020131999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11301020131999 - 223 = 11301011743391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11301020131949) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434654620449 + ... + 434654620474.

It is an arithmetic number, because the mean of its divisors is an integer number (3042582343234).

Almost surely, 211301020131999 is an apocalyptic number.

11301020131999 is a deficient number, since it is larger than the sum of its proper divisors (869309240937).

11301020131999 is an equidigital number, since it uses as much as digits as its factorization.

11301020131999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 869309240936.

The product of its (nonzero) digits is 13122, while the sum is 40.

The spelling of 11301020131999 in words is "eleven trillion, three hundred one billion, twenty million, one hundred thirty-one thousand, nine hundred ninety-nine".

Divisors: 1 13 869309240923 11301020131999