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11301030151 = 23491349137
BaseRepresentation
bin10101000011001100…
…00000100100000111
31002011120212210222021
422201212000210013
5141121030431101
65105220144011
7550023112525
oct124146004407
932146783867
1011301030151
11487a156244
122234838007
1310b13c62b8
14792c71315
154622035a1
hex2a1980907

11301030151 has 4 divisors (see below), whose sum is σ = 11792379312. Its totient is φ = 10809680992.

The previous prime is 11301030137. The next prime is 11301030161. The reversal of 11301030151 is 15103010311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11301030151 - 217 = 11300899079 is a prime.

It is a super-2 number, since 2×113010301512 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11301030101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245674546 + ... + 245674591.

It is an arithmetic number, because the mean of its divisors is an integer number (2948094828).

Almost surely, 211301030151 is an apocalyptic number.

11301030151 is a deficient number, since it is larger than the sum of its proper divisors (491349161).

11301030151 is an equidigital number, since it uses as much as digits as its factorization.

11301030151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 491349160.

The product of its (nonzero) digits is 45, while the sum is 16.

Adding to 11301030151 its reverse (15103010311), we get a palindrome (26404040462).

The spelling of 11301030151 in words is "eleven billion, three hundred one million, thirty thousand, one hundred fifty-one".

Divisors: 1 23 491349137 11301030151