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113010433202 = 256505216601
BaseRepresentation
bin110100100111111110…
…0100101110010110010
3101210200220001211101002
41221033330211302302
53322421132330302
6123525525442002
711110334555432
oct1511774456262
9353626054332
10113010433202
1143a22497137
1219a9ab70302
13a8700c5224
145680d442c2
152e1654cc02
hex1a4ff25cb2

113010433202 has 4 divisors (see below), whose sum is σ = 169515649806. Its totient is φ = 56505216600.

The previous prime is 113010433171. The next prime is 113010433213. The reversal of 113010433202 is 202334010311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 202334010311 = 281933717667.

It can be written as a sum of positive squares in only one way, i.e., 88727132641 + 24283300561 = 297871^2 + 155831^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28252608299 + ... + 28252608302.

Almost surely, 2113010433202 is an apocalyptic number.

113010433202 is a deficient number, since it is larger than the sum of its proper divisors (56505216604).

113010433202 is an equidigital number, since it uses as much as digits as its factorization.

113010433202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56505216603.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 113010433202 its reverse (202334010311), we get a palindrome (315344443513).

The spelling of 113010433202 in words is "one hundred thirteen billion, ten million, four hundred thirty-three thousand, two hundred two".

Divisors: 1 2 56505216601 113010433202