11301110300213 has 4 divisors (see below), whose sum is σ = 11301145160928. Its totient is φ = 11301075439500.

The previous prime is 11301110300209. The next prime is 11301110300237. The reversal of 11301110300213 is 31200301110311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11301110300213 - 2² = 11301110300209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11301110300191 and 11301110300200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11301119300213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16939481 + ... + 17593982.

It is an arithmetic number, because the mean of its divisors is an integer number (2825286290232).

Almost surely, 2^{11301110300213} is an apocalyptic number.

It is an amenable number.

11301110300213 is a deficient number, since it is larger than the sum of its proper divisors (34860715).

11301110300213 is an equidigital number, since it uses as much as digits as its factorization.

11301110300213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34860714.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11301110300213 its reverse (31200301110311), we get a palindrome (42501411410524).

The spelling of 11301110300213 in words is "eleven trillion, three hundred one billion, one hundred ten million, three hundred thousand, two hundred thirteen".