11301122214321 has 4 divisors (see below), whose sum is σ = 15068162952432. Its totient is φ = 7534081476212.

The previous prime is 11301122214271. The next prime is 11301122214409. The reversal of 11301122214321 is 12341222110311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11301122214321 - 2¹¹ = 11301122212273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11301122214291 and 11301122214300.

It is not an unprimeable number, because it can be changed into a prime (11301122214121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1883520369051 + ... + 1883520369056.

It is an arithmetic number, because the mean of its divisors is an integer number (3767040738108).

Almost surely, 2^{11301122214321} is an apocalyptic number.

It is an amenable number.

11301122214321 is a deficient number, since it is larger than the sum of its proper divisors (3767040738111).

11301122214321 is an equidigital number, since it uses as much as digits as its factorization.

11301122214321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3767040738110.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 11301122214321 its reverse (12341222110311), we get a palindrome (23642344324632).

It can be divided in two parts, 1130112 and 2214321, that added together give a palindrome (3344433).

The spelling of 11301122214321 in words is "eleven trillion, three hundred one billion, one hundred twenty-two million, two hundred fourteen thousand, three hundred twenty-one".